(7x-5)(3x^2+4x-4)=

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Solution for (7x-5)(3x^2+4x-4)= equation: 


Simplifying
(7x + -5)(3x2 + 4x + -4) = 0

Reorder the terms:
(-5 + 7x)(3x2 + 4x + -4) = 0

Reorder the terms:
(-5 + 7x)(-4 + 4x + 3x2) = 0

Multiply (-5 + 7x) * (-4 + 4x + 3x2)
(-5(-4 + 4x + 3x2) + 7x * (-4 + 4x + 3x2)) = 0
((-4 * -5 + 4x * -5 + 3x2 * -5) + 7x * (-4 + 4x + 3x2)) = 0
((20 + -20x + -15x2) + 7x * (-4 + 4x + 3x2)) = 0
(20 + -20x + -15x2 + (-4 * 7x + 4x * 7x + 3x2 * 7x)) = 0
(20 + -20x + -15x2 + (-28x + 28x2 + 21x3)) = 0

Reorder the terms:
(20 + -20x + -28x + -15x2 + 28x2 + 21x3) = 0

Combine like terms: -20x + -28x = -48x
(20 + -48x + -15x2 + 28x2 + 21x3) = 0

Combine like terms: -15x2 + 28x2 = 13x2
(20 + -48x + 13x2 + 21x3) = 0

Solving
20 + -48x + 13x2 + 21x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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